Coi $m_{dd\ HA} = 100(gam) \Rightarrow m_{dd\ H_2SO_4} = 100b(gam)$
$\Rightarrow m_{dd\ thu\ được} =1 00 +100b(gam)$
$m_{H_2SO_4} = 100b.85\% = 85b(gam)$
$m_{HA} = 100.a\% = a(gam)$
Ta có :
\(\dfrac{85b}{100+100b}.100\%=6\%\\ \dfrac{a}{100+100b}.100\%=20\%\)
Suy ra : a = \(\dfrac{1700}{79}\); b = \(\dfrac{6.}{79}\)