a,a-b+c-d=a+c-b-d=(a+c)-(b+d)(đpcm)
b,(a-b)-(c-d)=a-b-c+d=(a+d)-(b+c)(đpcm)
a, Ta có (a-b) +(c-d) = a-b+c-d = (a+c)-(b+d) ( ĐPCM)
b, Ta có (a-b)-(c-d) = a-b-c+d = ( a+d) - ( b+c) ( ĐPCM )
Tk mk nhé
a, \(\left(a-b\right)+\left(c-d\right)\)\(=a-b+c-d\)\(=a+c-b-d\)
\(=\left(a+c\right)-\left(b+d\right)\)
b, \(\left(a-b\right)-\left(c-d\right)\) \(=a-b-c+d=a+d-b-c=\left(a+d\right)-\left(b+c\right)\)
a) ( a-b)+(c-d)
= a-b+c-d
= (a+c)+(-b-d)
= (a+c)-(b+d)(ĐPCM)
b) (a-b)-(c-d)
= a-b-c+d
= (a+d)+(-b-c)
= (a+d)-(b+c)
a,
( a - b ) + ( c - d )
= a - b + c - d
= ( a + c ) - ( b + d ) ( đpcm )
b,
( a - b ) - ( c - d )
= a - b - c + d
= ( a + d ) - ( b + c ) ( đpcm )