\(\left(5x-3y+4z\right)\left(5x-3y-4z\right)=\left(5x-3y\right)^2-\left(4z\right)^2\)
\(=\left(3x-5y\right)^2-16z^2\)
Đẳng thức chỉ đúng khi \(z=0\)
Ta có:
\(\left(5x-3y+4z\right)\left(5x-3y-4z\right)\)
\(=\left(5x-3y\right)^2-16z^2\)
\(=25x^2-30xy+9y^2-16z^2\left(#\right)\)
Vì \(x^2=y^2+z^2\Rightarrow\left(#\right)=25x^2-30xy+9y^2-16\left(x^2-y^2\right)=\left(3x-5y\right)^2\)
(5x-3y+4z).(5x-3y-4z)=(3x-5y)2
<=>(5x-3y)2-16z2=(3x-5y)2
<=>(5x-3y)2-(3x-5y)2=16z2
<=>(8x-8y)(2x+2y)=16z2
<=>16(x2-y2)=16z2
<=>x2=y2+z2 (đúng với gt)