Đặt A = \(\frac{1}{3!}+\frac{1}{4!}+\frac{1}{5!}+....+\frac{1}{2000!}\)
Ta có:
\(\frac{1}{3!}
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Các câu hỏi tương tự
C=1/4^2+1/6^2+1/8^2+......+1/2000^2 cmr C<665/402
1)2/5+x:5/7=1/3
CMR: 2)B=1/2^2+1/3^2+1/4^2+1/5^2+1/6^2+1/7^2+1/8^2<1
3)CMR: S=3^2+3^3+...+3^101 chia hết cho 120
4)Cho S=5+5^2+5^3+...+5^2006
a) tính S
b)CMR S chia hết cho 6, và S chia hết cho 30
5) tìm số tự nhiên n sao cho 4n-5 chia hết cho 2n-1
1/M=1/1+2+3+1/1+2+3+4+1/1+2+3+4+5+...+1/1+2+3+4+..+59
cmr M>2/3
CMR(1/1*2+1/2*3+1/3*4+1/4*5+...+1/99*100):(1/51+1/52+1/53+...+1/100) = 1
1. Cho Ndfrac{1}{31}+dfrac{1}{32}+...+dfrac{1}{60}CMR dfrac{3}{5} N dfrac{4}{5}2. Cho Mdfrac{1}{3}-dfrac{2}{3^2}+dfrac{3}{3^3}-dfrac{4}{3^4}+...+dfrac{29}{3^{29}}-dfrac{30}{3^{30}}CMR M dfrac{3}{16}3. Cho Qdfrac{2}{3}+dfrac{8}{9}+dfrac{26}{27}+...+dfrac{3^{2021}-1}{3^{2021}}CMR Qdfrac{4041}{2}
Đọc tiếp
1. Cho N=\(\dfrac{1}{31}+\dfrac{1}{32}+...+\dfrac{1}{60}\)
CMR \(\dfrac{3}{5}< N< \dfrac{4}{5}\)
2. Cho M=\(\dfrac{1}{3}-\dfrac{2}{3^2}+\dfrac{3}{3^3}-\dfrac{4}{3^4}+...+\dfrac{29}{3^{29}}-\dfrac{30}{3^{30}}\)
CMR \(M< \dfrac{3}{16}\)
3. Cho Q=\(\dfrac{2}{3}+\dfrac{8}{9}+\dfrac{26}{27}+...+\dfrac{3^{2021}-1}{3^{2021}}\)
CMR \(Q>\dfrac{4041}{2}\)
CMR: 1/4<1/3^2+1/4^2+1/5^2+...+1/200^2<1/2
CMR A=1+1/2^2+1/3^2+1/4^2+1/5^2+...+1/2016^2<7/4
a) CMR: \(\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+...+\frac{1}{n^2}< \frac{3}{4}\)
b) CMR: \(\frac{1}{3^2}+\frac{1}{5^2}+\frac{1}{7^2}+...+\frac{1}{\left(2n+1\right)^2}< \frac{1}{4}\)
Bài 7 a) Chứng minh rằng
1 - 1/2 + 1/3 - 1/4 + 1/5 - 1/6 +......+ 1/1999 - 1/2000 = 1/1001 +1/1002+1/1003 +.....+ 1/2000