Question

CÍU EM VS !

Tìm x:

2^2x + 2^2x+1 = 48

 

Answer 1

\(2^{2x}+2^{2x+1}=48\)

\(2^{2x}+2^{2x}.2=48\)

\(2^{2x}.\left(1+2\right)=48\)

\(2^{2x}.3=48\)

\(2^{2x}=48:3\)

\(2^{2x}=16\)

\(2^{2x}=2^4\)

\(\Rightarrow2x=4\)

\(x=4:2\)

\(x=2\)

Answer 2

\(2^{2x}+2^{2x+1}=48\\ \Rightarrow2^{2x}+2.2^{2x}=48\\ \Rightarrow\left(1+2\right).2^{2x}=48\\ \Leftrightarrow3.2^{2x}=48\\ \Leftrightarrow2^{2x}=16\\ \Leftrightarrow2^{2x}=2^4\\ \Leftrightarrow2x=4\\ \Leftrightarrow x=2\)

Vậy x = 2

Answer 3

x = 2 

Answer 4

ok

Answer 5

ok