\(3\dfrac{2}{5}=\dfrac{17}{5}\)
\(7\dfrac{1}{8}=\dfrac{57}{8}\)
\(4\dfrac{5}{7}\)\(=\dfrac{33}{7}\)
\(3\dfrac{2}{5}=\dfrac{3\times5+2}{5}=\dfrac{17}{5}\)
\(7\dfrac{1}{8}=\dfrac{7\times8+1}{8}=\dfrac{57}{8}\)
\(4\dfrac{5}{7}=\dfrac{4\times7+5}{7}=\dfrac{33}{7}\)