Ta có:
abcd - (a + b + c + d)
= 1000a + 100b + 10c + d - a - b - c - d
= 999a + 99b + 9c
= 9.(111a + 11b + c) chia hết cho 9 (đpcm)
ta có
abcd-(a+b+c+d)
=1000a+100b+10c+d-a-b-c-d
=(1000a-a)+(100b-b)+(10c-c)+d
=999a+99b+9c+d
=9.111a+9.11b+9.c+d
=9.(111a+11b+c+d) chia hết cho9