\(x^2-x+1\ge\frac{3}{4}\)
\(\Leftrightarrow x^2-x+\frac{1}{4}\ge0\)
\(\Leftrightarrow x^2-2\cdot x\cdot\frac{1}{2}+\left(\frac{1}{2}\right)^2\ge0\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right)^2\ge0\)( luôn đúng )
Dấu "=" xảy ra \(\Leftrightarrow x=\frac{1}{2}\)