a)\(2^{29}+2^{30}=2^{29}\left(1+2\right)=2^{29}.3⋮3\)
Vậy \(2^{29}+2^{30}⋮3\)
c)\(^{3^{15}+3^{13}-3^{12}=3^{12}\left(3^3+3-1\right)=3^{12}\left(27+3-1\right)=29.3^{12}⋮29}\)
Vậy \(3^{15}+3^{13}-3^{12}⋮29\)
a, 2^30 + 2^29 chia hết cho 3
2^30= 2^29.2
ta có:
2^29.2+2^29.1 chia hết cho 3 hay 2^29.(1+2) chia hết cho 3
2^29.3 chia hết cho 3
b,