ta có:
1+21+22+23+24+25+26+27
=1+21+(22+23)+(24+25)+(26+27)
=(1+2)+22.(1+2)+24.(1+2)+26.(1+2)
=(1+2).(1+22+24+26)
=3.(1+22+24+26) chia hết cho 3
=>đpcm
=\(\left(1+2^1\right)+\left(2^2+2^3\right)+\left(2^4+2^5\right)+\left(2^6+2^7\right)\)
\(=\left(1+2\right)+2^2\left(1+2\right)+2^4\left(1+2\right)+2^6\left(1+2\right)\)
\(=3+2^2.3+2^4.3+2^6.3\)
\(=3\left(1+2^2+2^4+2^6\right)\) CHIA HẾT CHO 3
gọi C là tên biểu thức trên.ta có :
C = 1+21+22+23+24+25+26+27
C = ( 1 + 21 ) + ( 22 + 23 ) + ( 24 + 25 ) + ( 26 + 27 )
C = 3 + 22 . ( 1 + 21 ) + 24 . ( 1 + 21 ) + 26 . ( 1 + 21 )
C = 3 + 22 . 3 + 24 . 3 + 26 . 3
C = 3 . ( 1 + 22 + 24 + 26 ) chia hết cho 3