Đơn giản: \(\frac{5}{2}=\frac{5.\left(-1\right)}{2.\left(-1\right)}=\frac{-5}{-2}\)
Ta có: \(\frac{5}{2}=\frac{5\left(-1\right)}{2\left(-1\right)}\)
= \(\frac{-\left(5.1\right)}{-\left(2.1\right)}\)
=\(\frac{-5}{-2}\)
Vậy \(\frac{5}{2}=\frac{-5}{-2}\)(đpcm)
\(\frac{-5}{-2}=\frac{-5:\left(-1\right)}{-2:\left(-1\right)}=\frac{5}{2}\)
ta có \(\frac{a}{b}=\frac{c}{d}<=>a\cdot d=b\cdot c\)
mà : \(5\cdot\left(-2\right)=2\cdot\left(-5\right)\)
\(=>\frac{5}{2}=\frac{-5}{-2}\)