Các câu hỏi tương tự
Chứng minh rằng : \(\frac{1}{7^2}-\frac{1}{7^4}+...+\frac{1}{7^{4n-2}}-\frac{1}{7^{4n}}+...+\frac{1}{7^{98}}-\frac{1}{7^{100}}< \frac{1}{50}\)
Tìm số tự nhiên n sao cho \(\frac{1}{2}.\frac{5}{6}.\frac{9}{10}...\frac{4n+1}{4n+2}<\frac{1}{2014}<\frac{4}{5}.\frac{8}{9}.\frac{12}{13}...\frac{4n+4}{4n+4}\)
chứng minh rằng \(\frac{1}{7^2}-\frac{1}{7^4}+\frac{1}{7^6}-\frac{1}{7^8}+...+\frac{1}{7^{98}}-\frac{1}{7^{100}}<\frac{1}{50}\)
ai nhanh minh k cho
Chứng minh:
\(\frac{1}{7^2}-\frac{1}{7^4}+...+\frac{1}{4n-2}+\frac{1}{4n}+...+\frac{1}{98}+\frac{1}{100}<\frac{1}{50}\)
Chứng minh rằng: \(\frac{1}{6}<\frac{1}{^{5^2}}+\frac{1}{6^2}+\frac{1}{7^2}+\frac{1}{8^2}+...+\frac{1}{100^2}<\frac{1}{4}\)
Chứng minh \(\frac{1}{7^2}-\frac{1}{74}+...+\frac{1}{7^{4n-2}}-\frac{1}{7^{4n}}+...+\frac{1}{7^{98}}-\frac{1}{7^{100}}<\frac{1}{50}\)
Cho;A=\(\frac{1}{3^2}-\frac{1}{3^4}+\frac{1}{3^6}-\frac{1}{3^8}+......+\frac{1}{3^{98}}-\frac{1}{3^{100}}\)
Chứng minh rằng:
\(A=\frac{1}{2}\cdot\frac{3}{4}\cdot\frac{5}{6}\cdot\frac{7}{8}\cdot...\cdot\frac{99}{100}
Chứng minh rằng:
\(A=\frac{1}{2}\cdot\frac{3}{4}\cdot\frac{5}{6}\cdot\frac{7}{8}\cdot...\cdot\frac{99}{100}<\frac{1}{\sqrt{151}}\)