TC:a+b+cd=2p=>b+c=2p-a
=>(b+c)2=(2p-a)2
=>b2+2bc+c2=4p2-4pa+a2
=>b2+2bc+c2-a2=4p2-4pa
=>2bc+b2+c2-a2=4p(p-a) ĐPCM
Ta có : \(a+b+cd=2p\Rightarrow b+c=2p-a\)
\(\Rightarrow\left(b+c\right)^2=\left(2p-a\right)^2\)
\(\Rightarrow b^2+2bc+c^2=4p^2-4pa+a^2\)
\(\Rightarrow b^2+2bc+c^2-a^2=4p^2-4pa\)
\(\Rightarrow2bc+b^2+c^2-a^2=4p\left(p-a\right)\)
\(\RightarrowĐPCM\)