1/ Ta có:
A=2(1+2)+23(1+2)+....+259(1+2)=3(1+23+...+259) => A chia hết cho 3
2/ Ta có:
A=2(1+2+22)+24(1+2+22)+....+258(1+2+22)=7(2+24+...+258)
=> A chia hết cho 7
3/ Ta có:
A=2(1+2+22+23)+25(1+2+22+23)+....+257(1+2+22+23)=15(2+25+29+...+257)
Vậy A chia hết cho 15