A=(2+2^2)+...+(2^59+2^60)
=2(1+2)+...+2^59(1+2)
=3(2+2^3+...+2^59)
nên A chia hết cho 3.
A= (2+2^2+2^3)+...+(2^58+2^59+2^60)
=2(1+2+2^2)+...+2^58(1+2+2^2)
=7(2+2^4+..+2^58)
nên A chia hết cho 7
A= (2+2^2+2^3+2^4)+....+(2^57+2^58+2^59+2^6...
=2(1+2+2^2+2^3)+....+2^57(1+2+2^2+2^3)...
=15(2+2^5+...+2^57)
nên A chia hết cho 15