\(6\times\dfrac{3}{5}=\dfrac{18}{5};\dfrac{7}{2}+\dfrac{3}{10}=\dfrac{35}{10}+\dfrac{3}{10}=\dfrac{38}{10}=\dfrac{19}{5}\\ Ta.có:\dfrac{1}{10}< \dfrac{1}{2}< \dfrac{3}{5}< \dfrac{7}{10}< \dfrac{9}{10}< \dfrac{9}{7}< \dfrac{9}{5}< 3< \dfrac{18}{5}< \dfrac{19}{5}\\ \Leftrightarrow\dfrac{1}{10}< \dfrac{1}{2}< \dfrac{3}{5}< \dfrac{7}{10}< \dfrac{9}{10}< \dfrac{9}{7}< \dfrac{9}{5}< 3< 6\times\dfrac{3}{5}< \dfrac{7}{2}+\dfrac{3}{10}\)