x+y+z=0
=>x+y=-z
=>y+z=-x
=>z+x=-y
(1+x/y)(1+y/z)(1+z/x)
(y+x/y)(z+y/z)(x+z/x)
-z/y.-x/z.-y/x
=-1
x+y+z=0
=>x+y=-z
=>y+z=-x
=>z+x=-y
(1+x/y)(1+y/z)(1+z/x)
(y+x/y)(z+y/z)(x+z/x)
-z/y.-x/z.-y/x
=-1
Cho x.y.z khac 0 va x+y+z=0.Tính giá trị biểu thuc
A=(1+ x/y)(1+ y/z)(1+z/x)
Cho x,y,z khac 0 va x - y -z = 0. Tinh gia tri bieu thuc A = ( 1- z/x)(1-x/y)(1-y/z)
x;y;z khac 0 va x-y-z=0 . tinh B=(1- z/x).(1- x/y).(1+y/z)
Cho x,y,z khac o va x-y-z=0.Tinh gia tri cua bieu thuc A=(1-z/x)(1-x/y)(1+y/Z)
cho a/x=b/y=c/z=1/5 va x+y+z khac 0 tinh A=x+y+z/a+b+c
Cho x2=y.z ;y2=x.z va x+y+z khac 0 va x;y;z khac 0 Tinh A = (x+y+z)999/x222.y333.z444 Cac bn giup mk nha , mk se tra on
tim x;y;z;x va x;y;z khac 0 biet
(x.y-1)/y=(y.z-1)/z=(x.z-1)/x=1
cho cac so x,y,z khac 0 va thoa man \(\frac{1}{x}+\frac{1}{y}+\frac{1}{z}=0\) Chung minh rang x2(y+z)+y2(z+x ) +z2(x+z)+3xyz
ai nnha nhat minh tik dung luon
cho : B= x-y+z / x+2y -z va x/2 = y/5= z/7 va x+2y - z khac 0
tìm x,y , z