Đặt x/y=y/z=z/t=k
=>x=yk; y=zk; z=tk
=>x=yk; y=tk^2; z=tk
=>x=tk^3; y=tk^2; z=tk
\(\dfrac{x}{t}=\dfrac{tk^3}{t}=k^3\)
\(\left(\dfrac{x+y+z}{y+z+t}\right)^3=\left(\dfrac{tk^3+tk^2+tk}{tk^2+tk+t}\right)^3=\left(\dfrac{tk\left(k^2+k+1\right)}{t\left(k^2+k+1\right)}\right)^3=k^3\)
=>\(\dfrac{x}{t}=\left(\dfrac{x+y+z}{y+z+t}\right)^3\)
Đúng 2
Bình luận (1)