Dễ thấy: \(x_0;y_0\ne 0\)
*)Xét \(x_0;y_0>0\) xài BĐT AM-GM
\(x^3+y^3+1\ge3\sqrt[3]{x^3y^3}=3xy\)
Xảy ra khi \(x=y=1\)
Khi đó \(\left(1+x_0\right)\left(1+\dfrac{1}{y_0}\right)\left(1+\dfrac{x_0}{y_0}\right)=8\)
*)Xét \(x_0;y_0<0\)\(\Rightarrow3xy>0;x^3+y^3+1\le0\) (loại)