\(x^2y^2+1\ge2xy;y^2z^2+1\ge2yz;z^2x^2+1\ge2zx\)
\(\Rightarrow x^2y^2+y^2z^2+z^2x^2\ge2\left(xy+yz+zx\right)-3\)
\(\Rightarrow x^2+y^2+z^2+2\left(xy+yz+xz\right)-3\le6\)
\(\Rightarrow\left(x+y+z\right)^2-3\le6\)
\(\Rightarrow x+y+z\le3\)
Dấu " = " xảy ra khi \(x=y=z=1\)