\(2^x-2^y=1920\)
\(\Rightarrow2^y\left(2^{x-y}-1\right)=2^7.3.5\)
\(\Rightarrow\left\{{}\begin{matrix}2^y=2^7\\2^{x-y}-1=15\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}y=7\\2^{x-7}=16=2^4\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x-7=4\\y=7\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=11\\y=7\end{matrix}\right.\)
Vậy \(\left(x;y\right)=\left(11;7\right)\)
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