TL:
2 nhé
nhầm
s
-HT-
ta có:xy(x+y)=x2−xy+y2⇒1x+1y=1x2+1y2−1xy⇔1x+1y=14(1x+1y)2+34(1x−1y)2≥14(1x+1y)2⇒0≤1x+1y≤4xy(x+y)=x2−xy+y2⇒1x+1y=1x2+1y2−1xy⇔1x+1y=14(1x+1y)2+34(1x−1y)2≥14(1x+1y)2⇒0≤1x+1y≤4
mặt khác:A=1x3+1y3=(1x+1y)2≤16A=1x3+1y3=(1x+1y)2≤16
vậyMaxA=16;"="⇔x=y=12
TL:
x-y=12
-HT-
sai mik sorry nha
đúng k vậy=v
TL
Khi đó :
x-y =2
Hok tốt nha bn