Question

Cho tỉ lệ thức \(\frac{3x-y}{x+y}=\frac{1}{2}\). Giá trị của tỉ số \(\frac{x}{y}\) là bao nhiêu ?

Answer 1

Có \(\frac{3x-y}{x+y}=\frac{1}{2}\)

=> (3x- y).2 = x + y

=> 6x - 2y = x + y 

=> 5x = 3y

=> \(\frac{x}{y}=\frac{3}{5}\)

Answer 2

\(\frac{3x-y}{x+y}=\frac{1}{2}\)

\(\Rightarrow2\left(3x-y\right)=x+y\)

\(\Rightarrow6x-2y=x+y\)

\(\Rightarrow5x=3y\)

\(\Rightarrow\frac{x}{y}=\frac{3}{5}\)

Vậy :................

Answer 3

\(\frac{3x-y}{x+y}=\frac{1}{2}\)

\(\Rightarrow2\left(3x-y\right)=x+y\)

\(\Rightarrow6x-2y=x+y\)

\(\Rightarrow5x=3y\)

\(\Rightarrow\frac{x}{y}=\frac{3}{5}\)

Vậy \(\frac{x}{y}=\frac{3}{5}\)