Giải:
Ta có : a/b = c/d => a/c = b/d
Đặt a/c = b/d = k => a = ck ; b = dk
Khi đó, ta có : \(\frac{2012.ck+2013.dk}{2012.ck-2013.dk}=\frac{\left(2012c+2013d\right).k}{\left(2012c-2013d\right).k}=\frac{2012c+2013d}{2012c-2013d}\)(đpcm)
Giải:
Ta có : a/b = c/d => a/c = b/d
Đặt a/c = b/d = k => a = ck ; b = dk
Khi đó, ta có : \(\frac{2012.ck+2013.dk}{2012.ck-2013.dk}=\frac{\left(2012c+2013d\right).k}{\left(2012c-2013d\right).k}=\frac{2012c+2013d}{2012c-2013d}\)(đpcm)
Cho a/b=c/d.CM 2010a+2011b/2010c+2011d=2012a-2013b/2012c-2013d
cho\(\frac{a}{2b}\)=\(\frac{b}{2c}=\frac{c}{2d}=\frac{d}{2a}\)(a, b, c, d > 0). Tính:
A=\(\frac{2013a-2012b}{c+d}+\frac{2013b-2012c}{a+d}+\frac{2013c-2012d}{a+b}+\frac{2013d-2012a}{b+c}\)
Tìm x biết
a)\(||3x-\frac{7}{3}|-2|=7\)
b) Cho \(\frac{a}{2b}=\frac{b}{2c}=\frac{c}{2d}=\frac{d}{2a}\)(a, b, c, d > 0). Tính
A = \(\frac{2013a-2012b}{c+d}+\frac{2013b-2012c}{a+d}+\frac{2013c-2012d}{a+b}+\frac{2013d-2012a}{b+c}\)
CHO \(\frac{a}{2b}\)=\(\frac{b}{2c}\)=\(\frac{c}{2d}\)=\(\frac{d}{2a}\) (a,b,c,d > 0).TÍNH:
A=\(\frac{2013a-2012b}{c+d}\)+\(\frac{2013b-2012c}{a+d}\)+\(\frac{2013c-2012d}{a+b}\)+\(\frac{2013d-2012a}{b+c}\)
Cho dãy tỉ số bằng nhau : \(\frac{2012a+b+c+d}{a}=\frac{a+2012b+c+d}{b}=\frac{a+b+2012c+d}{c}=\frac{a+b+c+2012d}{d}\).Tính giá trị biểu thức: M=\(\frac{a+b}{c+d}+\frac{b+c}{d+a}+\frac{c+d}{a+b}+\frac{d+a}{b+c}\)
cho dãy tỉ số bằng nhau
\(\frac{2012a+b+c+d}{a}=\frac{a+2012b+c+d}{b}=\frac{a+b+2012c+d}{c}=\frac{a+b+c+2012d}{d}\)
tính \(M=\frac{a+b}{c+d}+\frac{b+c}{d+a}+\frac{c+d}{a+b}+\frac{d+a}{b+c}\)
Cho dãy tỉ số bằng nhau:
\(\frac{2012a+b+c+d}{a}=\frac{a+2012b+c+d}{b}=\frac{a+b+2012c+d}{c}=\frac{a+b+c+2012d}{d}\)
tính M =\(\frac{a+b}{c+d}+\frac{b+c}{d+a}+\frac{c+d}{a+b}+\frac{d+a}{b+c}\)
cho dãy tỉ số bằng nhau
\(\frac{2012a+b+c+d}{a}=\frac{a+2012b+c+d}{b}=\frac{a+b+2012c+d}{c}=\frac{a+b+c+2012d}{d}\)
tính M=\(\frac{a+b}{c+d}+\frac{b+c}{d+a}+\frac{c+d}{a+b}+\frac{d+a}{b+c}\)
cho dãy tỉ số bằng nhau
\(\frac{2012a+b+c+d}{a}=\frac{a+2012b+c+d}{b}=\frac{a+b+2012c+d}{c}=\frac{a+b+c+2012d}{d}\)
Tính M= \(\frac{a+b}{c+d}+\frac{b+c}{d+a}+\frac{c+d}{a+b}+\frac{d+a}{b+c}\)