Question

cho sinx α =\(\dfrac{-4}{5}\) và π<α<\(\dfrac{\Pi}{2}\) thì sinx α bằng bao nhiêu?

Answer 1

\(sin^2\alpha=1-sin^2\alpha=1-\left(\dfrac{-4}{5}\right)^2=\dfrac{9}{25}\)

vì π<α<\(\dfrac{3\Pi}{2}\)⇒cos α =\(\dfrac{-3}{5}\)

Answer 2

cos²a =1- sin²a =1-\(\left(\dfrac{-4}{5}\right)^2\)=\(\dfrac{3}{5}\)

Vì π<a<\(\dfrac{3\pi}{2}\)

=>cos a =\(\dfrac{-3}{5}\)