Question

^{cho S=\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2011}-\frac{1}{2012}+\frac{1}{2013}\)}và P=\(\frac{1}{1007}+\frac{1}{1008}+...+\frac{1}{2013}\)

Tính (S-P)²¹³

Answer 1

S=\(\left(1+\frac{1}{3}+...+\frac{1}{2013}\right)-\left(\frac{1}{2}-\frac{1}{4}-...-\frac{1}{2012}\right)\)

S=\(\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2013}\right)-2\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{2012}\right)\)

S=\(\left(\text{​​}\text{​​}\text{​​}1+\frac{1}{2}+...+\frac{1}{2013}\right)-1-\frac{1}{2}-...-\frac{1}{2012}\)

S=\(\frac{1}{1007}+\frac{1}{1008}+...+\frac{1}{2013}\)

=>S=P

=>S-P=0

=>(S-P)^2013=0

Answer 2

toi lam roi 144                  100% dung 

Answer 3

sai do  2013 = 0

Answer 4

144 ban a

Answer 5

sai rồi tung nguyen viet