Vì nếu rút gọn \(\frac{a}{b}\)thì được phân số \(\frac{9}{13}\)=> \(\frac{a}{b}=\frac{9k}{13k}\left(k\in Z;k\ne0\right)\)
Ta có: \(\frac{9k}{13k-35}=\frac{27}{32}\)
=> \(9.k.32=27.\left(13.k-35\right)\)
=> \(288.k=351.k-945\)
=> \(351.k-288.k=945\)
=> \(63.k=945\)
=> \(k=945:63=15\)
=> \(\frac{a}{b}=\frac{9.15}{13.15}=\frac{135}{195}\)