a) Ta có : \(\frac{a}{b}=\frac{a\left(b+c\right)}{b\left(b+c\right)}=\frac{ab+ac}{b\left(b+c\right)}\)
\(\frac{a+c}{b+c}=\frac{b\left(a+c\right)}{b\left(b+c\right)}=\frac{ab+bc}{b\left(b+c\right)}\)
Vì 0<a<b nên ab+ac<ab+bc
\(\Rightarrow\frac{ab+ac}{b\left(b+c\right)}>\frac{ab+bc}{b\left(b+c\right)}\)
hay \(\frac{a}{b}< \frac{a+c}{b+c}\)
Vậy \(\frac{a}{b}< \frac{a+c}{b+c}\)