a: Sửa đề: Chứng minh \(\hat{ABC}=\hat{BAN}\)
Ta có: \(\hat{NAF}+\hat{NAB}=180^0\) (hai góc kề bù)
\(\hat{ABC}+\hat{CBE}=180^0\) (hai góc kề bù)
mà \(\hat{CBE}=\hat{NAF}\)
nên \(\hat{NAB}=\hat{ABC}\)
b: ta có: \(\hat{NAB}=\hat{ABC}\)
\(\hat{NAB}+\hat{MAB}=180^0\) (hai góc kề bù)
Do đó: \(\hat{MAB}+\hat{ABC}=180^0\)


