a,DB//At⇒\(\widehat{tAB}=\widehat{ABD}=32^o\left(2.góc.so.le.trong\right)\)
b,Ta có:\(\widehat{tCB}+\widehat{CBD}=58^o+122^o=180^o\)
Mà 2 góc này là 2 góc trong cùng phía⇒Ci//DB
Mà DB//At⇒Ci//At
c, Ta có:\(\widehat{ABC}=\widehat{ABD}+\widehat{DBC}=32^o+58^o=90^o\Rightarrow AB\perp BC\)