Question

Cho hàm số y = f(x) = 3x + 29 - 2. Tìm f(0), f(4), f(-3), f(5)

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Answer 1

Trả lời:

\(f\left(0\right)=3.0+29-2=27\)

\(f\left(4\right)=3.4+29-2=39\)

\(f\left(-3\right)=3.\left(-3\right)+29-2=18\)

\(f\left(5\right)=3.5+29-2=42\)

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Answer 2

42 nha!!!!!!!!!!!!!!!!!!!!!

Answer 3

k true kamado tanajirou

Answer 4

\(y=f\left(x\right)-3x+29-2\)

\(y=f\left(0\right)=3\cdot0+29-2=27\)

\(y=f\left(4\right)=3\cdot4+29-2=39\)

\(y=f\left(-3\right)=3\cdot\left(-3\right)+29-2=18\)

\(y=f\left(5\right)=3\cdot5+29-2=42\)

Answer 5

Ta có 

TH1 : \(f\left(0\right)=3.0+29-2=0+29-2=27\)

TH2 : \(f\left(4\right)=3.4+29-2=12+27=39\)

TH3 : \(f\left(-3\right)=3\left(-3\right)+29-2=-9+27=18\)

TH4 : \(f\left(5\right)=3.5+29-2=15+27=42\)

Answer 6

y = f(x) = 3x + 29 - 2 . Tìm f(0), f(4), f(-3), f(5).

BL:

y = f(0) = 3.0 + 29 - 2 = 29 - 2 = 27

y = f(4) = 3.4 + 29 - 2 = 12 +29 - 2 = 39

y = f(-3) = 3.(-3) +29 -2 = -9 +29 - 2 = 18

y = f(5) = 3.5 + 29 - 2 = 15 + 29 - 2 = 42

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