Fx)=G(x) <=> x3+4x2-3x+2=x2(x+4)+x-5
<=> x3+4x2-3x+2=x3+4x2+x-5
<=> 4x=7 => x=7/4
Đáp số: x=7/4
\(F\left(x\right)=G\left(x\right)\)
\(\Leftrightarrow\)\(x^3+4x^2-3x+2=x^2\left(x+4\right)+x-5\)
\(\Leftrightarrow\)\(x^3+4x^2-3x+2=x^3+4x^2+x-5\)
\(\Leftrightarrow\)\(-4x=-7\)
\(\Leftrightarrow\)\(x=\frac{7}{4}\)
Vậy...