Question

Cho \(\frac{3x-y}{x+y}=\frac{3}{4}.Tính\frac{x}{y}\)

Answer 1

\(\frac{3x-y}{x+y}=\frac{3}{4}\)

<=> (3x - y) . 4 = (x + y) . 3

<=> 12x - 4y = 3x + 3y

<=> 12x - 3x = 3y + 4y

<=> 9x = 7y

<=> \(\frac{x}{y}=\frac{7}{9}\)

Answer 2

\(\frac{3x-y}{x+y}=\frac{3}{4}\)

=>(3x-y).4=(x+y).3

=>12x-4y=3x+3y

=>12x-4x=3y+4y

=>8x=7y

=>\(\frac{x}{y}=\frac{7}{8}\)

Answer 3

Mình nhầm

\(\frac{x}{y}=\frac{7}{9}\)

Answer 4

Bài này nãy làm rồi thì phải