\(\text{1 +2 +3 +...+99+100}=\frac{\left(100+1\right).100}{2}=\frac{10100}{2}=5050\)
tớ giải cho rồi đấy hot boy 6C
nhớ tick nha
tinh gia tri bieu thuc [1+1/100] * [1+1/99]*.....* [1+1/3] * [1+1/2]
tinh gia tri bieu thuc : a ) : (1+2+3+4+ .............+97+98+99+100) : 5
cho A= a+a+a+...+a-99(co 99 so a) a hay tinh gia tri bieu thuc a= 1001| b tinh so tu nhien a de bieu thua a = 1990+702:(a-6) co gia tri nho nhat
Tinh gia tri cua bieu thuc :
3/4 nhan 8/9 nhan 15/16 nhan ...nhan 99/100 =
B=5,76xa+4,24xa
tim gia tri de B nho nhat
2
cho hinh chu nhat co chu vi la 162m . Nguoi ta tang chieu dai moi ben 3m de ra 1 hinh thang can th dien tang 168mvuong
a)hay ve hinh va tinh day lon hinh thang
b)tinh dien tich hinh thang
tinh gia tri bieu thuc a = \(\sqrt{4+\sqrt[3]{8}+\frac{2}{3}}+3^{10}\frac{1}{1\times2}+\frac{1}{2\times3}+...+\frac{1}{99\times100}\)
tinh gia tri bieu thuc a = \(\sqrt{4+\sqrt[3]{8+\frac{2}{3}+3^{10}\frac{1}{1\times2}+\frac{1}{2\times3}+...+\frac{1}{99\times100}}}\)
tinh gia tri bieu thuc a = \(\sqrt{4+\sqrt[3]{8+\frac{2}{3}+3^{10}\frac{1}{1\times2}+\frac{1}{2\times3}+...+\frac{1}{99\times100}}}\)
bai 1
cho day so 1 , 4 , 7 , 10, ... 97 , 100
hay cho biet ay so tren co bao nhieu so hang ?
bai 2 cho day so 31 , 35 , 39 , 43 , ... 99 , 103
tinh tong cac so hang cua tren
