Question

Cho các số \(x,y,z\) thỏa mãn: \(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}\) và \(2x+3y-z=95\)

Khi đó \(x,y,z=\)

Answer 1

\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}=\frac{2\left(x-1\right)+3\left(y-2\right)-\left(z-3\right)}{2.2+3.3-4}=\frac{95-5}{9}=10\)

x-1 =20 => x =21

y-2 =30 => y =32

z-3 =40 => z =43

Answer 2

\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}=\frac{2x-2+3y-6-z+3}{4+9-4}=\frac{90}{9}=10\)

\(\Rightarrow\) x - 1 = 20; y - 2 = 30; z - 3 = 40

\(\Rightarrow\) x = 21; y = 32; z = 43