\(A=\left(-a-b+c\right)-\left(-a-b-c\right)\)
\(A=-a-b+c+a+b+c\)
\(A=\left(-a+a\right)+\left(b-b\right)+\left(c+c\right)\)
\(\Rightarrow A=2c\)
\(A=\left(-a-b+c\right)-\left(-a-b-c\right)\)
\(A=-a-b+c+a+b+c\)
\(A=2c\)
Vậy \(A=2c\)
\(A=(-a-b-c)-(-a-b-c)\)
\(=(-a-b-c)+(a-b-c)\)
\(=(-a+a)+(b-b)+(c+c)\)
\(=2c\)
Vậy A = 2c
Học tốt
\(A=\left(-a-b+c\right)-\left(-a-b-c\right)\)
\(A=-a-b+c+a+b+c\)
\(A=\left(-a+a\right)+\left(-b+b\right)+\left(c+c\right)\)
\(A=2c\)