A=x3/x2--4.x+2/x-x-4xx-4/xx-2
Điều kiện x \(\ne\)+-2
Ý b c tự làm
\(A=\frac{x^3}{x^2-4}.\frac{x+2}{x}-\frac{4x-4}{x-2}\) \(ĐKXĐ:x\ne0;x\ne2\)
\(A=\frac{x^2}{x-2}-\frac{4\left(x-1\right)}{x-2}\)
\(A=\frac{x^2-4x+4}{x-2}\)
\(A=\frac{\left(x-2\right)^2}{x-2}\)
\(A=x-2\)
vậy \(A=x-2\)