Question

Cho: \(A=\frac{1}{2}+\frac{3}{2}+(\frac{3}{2})^2+(\frac{3}{2})^3+(\frac{3}{2})^4+...+(\frac{3}{2})^{2012}\)   và       \(B=(\frac{3}{2})^{2013}:2\)

Tính B-A.

Mình đang cần gấp. ai nhanh và đúng thì mình tick cho.

Answer 1

k chép đề

3/2.A=\(\frac{3}{4}+\left(\frac{3}{2}\right)^2+\left(\frac{3}{2}\right)^3+\left(\frac{3}{2}\right)^4+\left(\frac{3}{2}\right)^5+...+\left(\frac{3}{2}\right)^{2013}\)

3/2A-A=(\(\frac{3}{4}+\left(\frac{3}{2}\right)^2+\left(\frac{3}{2}\right)^3+\left(\frac{3}{2}\right)^4+\left(\frac{3}{2}\right)^5+...+\left(\frac{3}{2}\right)^{2013}\)) - (\(\frac{1}{2}+\frac{3}{2}+\left(\frac{3}{2}\right)^2+\left(\frac{3}{2}\right)^3+\left(\frac{3}{2}\right)^4+...+\left(\frac{3}{2}\right)^{2012}\))

1/2 . A =\(\frac{1}{2}+\left(\frac{3}{2}\right)^{2013}\)

A=\(\frac{\frac{1}{2}+\left(\frac{3}{2}\right)^{2013}}{2}\)

B-A=\(\frac{\left(\frac{3}{2}\right)^{2018}}{2}-\)\(\frac{\frac{1}{2}+\left(\frac{3}{2}\right)^{2013}}{2}\)

\(B-A=\frac{\frac{1}{2}}{2}=\frac{1}{2}:2=\frac{1}{4}\)

Answer 2

à chết  Nguyễn Thị Hiền  ơi câu cuối mik quên mất

B-A=\(\frac{\frac{-1}{2}}{2}\)

B-A=\(\frac{-1}{4}\) nhé

cám ơn đã đọc