giúp mk vs mn ơi. mình cần gấp chiều mai nộp òi
Các câu hỏi tương tự
\(\left(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+.....+\frac{1}{2017.2018}\right)-\left(\frac{1}{1010}+\frac{1}{1011}+\frac{1}{1012}+.....+\frac{1}{2017}\right)\)
tính hợp lí:
\(\left(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{2017.2018}\right)-\left(\frac{1}{1010}+\frac{1}{1011}+...+\frac{1}{2018}\right)\)
Chứng minh rằng:
a)\(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}< \frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{99.100}\)
b)\(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{99.100}< 1-\frac{1}{2.3}\)
Cần gấp, ai nhanh mik tick nha
Cho A=\(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}.....+\frac{1}{2013.2014}\)và B=\(\frac{1}{2016}+\frac{1}{2018}+\frac{1}{2020}+....+\frac{1}{4028}\)
Tính \(\frac{A}{B}\)
â , tính M = \(\left(1+\frac{1}{2}\right)\left(1+\frac{1}{3}\right).......\left(1+\frac{1}{2017}\right)\left(1+\frac{1}{2018}\right)\)
b , Cho A = \(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+.....+\frac{1}{2017}-\frac{1}{2018}\)
c , B = \(\frac{1}{1010}+\frac{1}{1011}+.....+\frac{1}{2017}+\frac{1}{2018}.tinh\left(\frac{A}{B}\right)^{2018}\)
Tính \(\left(M-N\right)^2\)với \(M=1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{2017}-\frac{1}{2018}+\frac{1}{2019}\)
và \(N=\frac{1}{1010}+\frac{1}{1011}+....+\frac{1}{2019}\)
Cho A=\(\frac{1}{1011}\left(1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{2019}\right)\)và B=\(\frac{1}{1010}\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+\frac{1}{2020}\right)\)So sánh A và B
Tính C=(1/1.2+1/3.4+1/5.6+...+1/2017.2018)-(1/1010+1/1011+1/1012+...+1/2017)
Tính A/B biết
A=\(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{17.18}+\frac{1}{19.20}\)
B=\(\frac{1}{11}+\frac{1}{12}+\frac{1}{13}+...+\frac{1}{19}+\frac{1}{20}\)