Ta có : \(\left(a+b+c\right)\left(\frac{1}{a+b}+\frac{1}{b+c}+\frac{1}{c+a}\right)=2015.5\)
\(\Leftrightarrow\frac{a}{b+c}+\frac{b}{c+a}+\frac{c}{a+b}+\frac{a+b}{a+b}+\frac{a+c}{c+a}+\frac{b+c}{b+c}=2015.5\)
\(\Leftrightarrow Q+3=2015.5\Rightarrow Q=2015.5-3=10072\)