\(\frac{1}{ab+a+1}+\frac{b}{bc+b+1}+\frac{1}{abc+bc+b}\)
\(=\frac{1}{ab+a+1}+\frac{b}{bc+b+1}+\frac{1}{1+bc+b}\)
\(=\frac{1}{ab+a+1}+\frac{a.b}{a.\left(bc+b+1\right)}+\frac{1.a}{a.\left(1+bc+b\right)}\)
\(=\frac{1}{ab+a+1}+\frac{ab}{abc+ab+a}+\frac{a}{a+abc+ab}\)
\(=\frac{1}{ab+a+1}+\frac{ab}{ab+a+1}+\frac{a}{ab+a+1}=\frac{ab+a+1}{ab+a+1}=1\)
cho 3 số a,b,c thõa mãn : a.b.c=1
C/M : \(\frac{1}{ab+a+1}+\frac{b}{bc+b+1}+\frac{1}{abc+bc+b}=1\)1
Cho a.b.c=1
CMR: (1/1+ab+a) +(1/bc+b+a)+(1/abc+bc+b)=1
cho số a,b,c thỏa mãn : a.b.c= 1
chứng minh : \(\frac{1}{ab+a+1}+\frac{1}{bc+b+1}+\frac{1}{abc+bc+b}=1\)
Cho 3 số tự nhiên a.b.c=1.Chứng minh rằng:
(1/ab+a+1)+(b/bc+b+1)+(1/abc+bc+1)
help me huhu
Cho a, b, c thỏa mãn a.b.c=1
Tính: S = 1/(1+a+ab) + 1/(1+b+bc) + 1/(1+c+ca)
cho a.b.c=1 tính \(\frac{1}{ab+a+1}\)+\(\frac{b}{bc+b+1}\)+\(\frac{1}{abc+bc+b}\)
giúp mk với
Cho a.b.c = 1.Tính :
\(\frac{a}{ab+a+1}+\frac{b}{bc+b+1}+\frac{c}{ca+c+1}\)
Cho a,b,c thỏa mãn a.b.c = 1
Chứng minh rằng: \(\frac{1}{ab+a+1}\) + \(\frac{1}{bc+b+1}\) + \(\frac{1}{abc+bc+b}\) = 1
cho a.b.c=1. tính A = \(\frac{a}{ab+a+1}+\frac{b}{bc+b+1}+\frac{c}{ac+c+1}\)
