Chính bài của em:
Chính bài của em:
Cho \(a,b,c\ge1\). CMR:
\(a\left(b+c\right)+b\left(c+a\right)+c\left(a+b\right)+2\left(\dfrac{1}{a^2+1}+\dfrac{1}{b^2+1}+\dfrac{1}{c^2+1}\right)\ge9\)
Cho a, b, c>0; abc=1. Cmr:
\(\dfrac{a^3}{b\left(c+2\right)}+\dfrac{b^3}{c\left(a+2\right)}+\dfrac{c^3}{a\left(b+2\right)}\ge1\)
Sao em làm chỉ ra >=3 thôi ạ)):
cho a,b,c>0, CMR:
\(\left(a+b+\dfrac{1}{4}\right)^2+\left(b+c+\dfrac{1}{4}\right)^2+\left(c+a+\dfrac{1}{4}\right)^2\ge4\left(\dfrac{1}{\dfrac{1}{a}+\dfrac{1}{b}}+\dfrac{1}{\dfrac{1}{b}+\dfrac{1}{c}}+\dfrac{1}{\dfrac{1}{c}+\dfrac{1}{a}}\right)\)
1. Biết a, b, c đôi 1 khác nhau . Chứng miinh rằng :
\(\dfrac{b-c}{\left(a-b\right)\left(a-c\right)}+\dfrac{c-a}{\left(b-c\right)\left(b-a\right)}+\dfrac{a-b}{\left(c-a\right)\left(c-b\right)}=\dfrac{2}{a-b}+\dfrac{2}{b-c}+\dfrac{2}{c-a}\).
2. Cho x,y,z đôi một khác nhau thoả mãn \(\dfrac{xy+1}{y}+\dfrac{yz+1}{z}+\dfrac{zx+1}{x}\). Chứng minh rằng : \(\left|xyz\right|=1\)
Cho a,b,c>0 thỏa mãn : \(ab+bc+ca=0\)
C/m: \(\dfrac{1}{ab}+\dfrac{1}{bc}+\dfrac{1}{ca}\ge3+\sqrt{\dfrac{\left(a+b\right)\left(a+c\right)}{a^2}}+\sqrt{\dfrac{\left(b+c\right)\left(b+a\right)}{b^2}}+\sqrt{\dfrac{\left(c+a\right)\left(c+b\right)}{c^2}}\)
Cho các số dương a,b,c thỏa mãn \(\left\{{}\begin{matrix}a+b+c=2\\a^2+b^2+c^2=2\end{matrix}\right.\)
Chứng minh rằng: \(a\sqrt{\dfrac{\left(1+b^2\right)\left(1+c^2\right)}{1+a^2}}+b\sqrt{\dfrac{\left(1+a^2\right)\left(1+c^2\right)}{1+b^2}}+c\sqrt{\dfrac{\left(1+a^2\right)\left(1+b^2\right)}{1+c^2}}=2\)
Chứng minh rằng biểu thức sau không phụ thuộc a, b, c: \(B=\dfrac{4a^2-1}{\left(a-b\right)\left(a-c\right)}+\dfrac{4b^2-1}{\left(b-c\right)\left(b-a\right)}+\dfrac{4c^2-1}{\left(c-a\right)\left(c-b\right)}\)
cho các số thực không âm a , b , c ( a khác b ) thỏa mãn (a+c)(b+c)=1
Tìm min A \(\dfrac{1}{\left(a-b\right)^2}\)+\(\dfrac{1}{\left(a+c\right)^2}\)+\(\dfrac{1}{\left(b+c\right)^2}\)
Cho a, b, c là độ dài 3 cạnh tam giác. CMR:
1, \(\dfrac{1}{\left(a+b-c\right)^n}+\dfrac{1}{\left(a-b+c\right)^n}+\dfrac{1}{\left(b+c-a\right)^n}\ge\dfrac{1}{a^n}+\dfrac{1}{b^n}+\dfrac{1}{c^n}\)
2, \(\dfrac{1}{a^n}+\dfrac{1}{b^n}+\dfrac{1}{c^n}\ge4^n\left[\dfrac{1}{\left(2a+b+c\right)^n}+\dfrac{1}{\left(a+2b+c\right)^n}+\dfrac{1}{\left(a+b+2c\right)^n}\right]\)