Question

cho các số thực không âm a , b , c ( a khác b ) thỏa mãn (a+c)(b+c)=1

Tìm min A \(\dfrac{1}{\left(a-b\right)^2}\)+\(\dfrac{1}{\left(a+c\right)^2}\)+\(\dfrac{1}{\left(b+c\right)^2}\)

Answer 1

Đặt \(\left\{{}\begin{matrix}a+c=x>0\\b+c=y>0\end{matrix}\right.\) \(\Rightarrow xy=1\)

\(A=\dfrac{1}{\left(x-y\right)^2}+\dfrac{1}{x^2}+\dfrac{1}{y^2}=\dfrac{1}{\left(x-y\right)^2}+\dfrac{x^2+y^2}{x^2y^2}\)

\(=\dfrac{1}{\left(x-y\right)^2}+x^2+y^2-2xy+2xy\)

\(=\dfrac{1}{\left(x-y\right)^2}+\left(x-y\right)^2+2\ge2\sqrt{\dfrac{\left(x-y\right)^2}{\left(x-y\right)^2}}+2=4\)