https://olm.vn/hoi-dap/question/764972.html
Gõ link mk gửi là có, link mà đang chờ duyệt ấy
Ta có: \(M=\frac{2015a}{ab+2015a+2015}+\frac{b}{bc+b+2015}\) \(+\frac{c}{ac+c+1}\)
\(=\frac{2015ac}{abc+2015ac+2015c}+\frac{b}{bc+b+abc}\) \(+\frac{c}{ac+c+1}\)
\(=\frac{2015ac}{2015\left(1+ac+c\right)}+\frac{b}{b\left(c+1+ac\right)}\)\(+\frac{c}{ac+c+1}\)
\(=\frac{ac}{ac+c+1}+\frac{1}{ac+c+1}+\frac{c}{ac+c+1}\) \(=\frac{ac+c+1}{ac+c+1}=1\)
\(\Rightarrow M=1\)