\(a^3+6=-3a-2a^2\)
\(\Leftrightarrow a^3+6+3a+2a^2=0\)
\(\Leftrightarrow a^2.\left(a+2\right)+3.\left(a+2\right)=0\)
\(\Leftrightarrow\left(a^2+3\right).\left(a+2\right)=0\Leftrightarrow a+2=0\Leftrightarrow a=-2\left(\text{vì }a^2+3\ge3\right)\)
Thay a=-2, vào A ta có:
\(A=\frac{-2-1}{-2+3}=-3\)