ta có a/b+c+b/a+c+c/a+b=1
=> (a+b+c)(a/b+c+b/a+c+c/a+b)=a+b+c
=> a^2/b+c+ab/a+c+ac/a+b+ba/b+c+b^2/a+c+bc/a+b+ca/b+c+bc/a+c+c^2/a+b=a+b+c
=> a^2/b+c+(ba/b+c+ca/b+c)+b^2/a+c+(ab/a+c+bc/a+c)+c^2/a+b+(ac/a+b+bc/a+b)=a+b+c
=>( a^2/b+c)+a+(b^2/a+c)+b+(c^2/a+b)+c=a+b+c
=> a^2/b+c+b^2/a+c+c^2/a+b=0