\(a,n_{Zn}=\dfrac{5,6}{65}=\dfrac{28}{325}\left(mol\right)\)
PTHH: Zn + 2HCl ---> ZnCl2 + H2
\(\dfrac{28}{325}\)-->\(\dfrac{56}{325}\)----->\(\dfrac{28}{325}\)--->\(\dfrac{28}{325}\)
=> \(\left\{{}\begin{matrix}b,V_{H_2}=\dfrac{28}{325}.22,4=1,93\left(l\right)\\c,m_{muối}=\dfrac{28}{325}.136=11,72\left(g\right)\\d,C_{M\left(HCl\right)}=\dfrac{\dfrac{56}{325}}{0,1}=1,72M\end{matrix}\right.\)