\(n_{SO_2}=\dfrac{4.48}{22.4}=0.2\left(mol\right)\)
\(n_{KOH}=0.25\cdot1=0.25\left(mol\right)\)
\(\dfrac{n_{KOH}}{n_{SO_2}}=\dfrac{0.25}{0.2}=1.25\)
\(\rightarrow\text{Phản ứng tạo ra 2 muối }\)
\(n_{K_2SO_3}=a\left(mol\right)\)
\(n_{KHSO_3}=b\left(mol\right)\)
\(\left\{{}\begin{matrix}2a+b=0.25\\a+b=0.2\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}a=0.05\\b=0.15\end{matrix}\right.\)
\(m_{\text{Muối}}=0.05\cdot158+0.15\cdot100=22.9\left(g\right)\)
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