\(n_{MgO}=\dfrac{4}{40}=0,1\left(mol\right)\)
Pt : \(MgO+2HCl\rightarrow MgCl_2+H_2O|\)
1 2 1 1
0,1 0,2 0,1
a) \(n_{HCl}=\dfrac{0,1.2}{1}=0,2\left(mol\right)\)
⇒ \(m_{HCl}=0,2.36,5=7,3\left(g\right)\)
\(C_{HCl}=\dfrac{7,3.100}{300}=2,43\)0/0
b) \(n_{MgCl2}=\dfrac{0,2.1}{2}=0,1\left(mol\right)\)
⇒ \(m_{MgCl2}=0,1.95=9,5\left(g\right)\)
\(m_{ddspu}=4+300=304\left(g\right)\)
\(C_{MgCl2}=\dfrac{9,5.100}{304}=3,125\)0/0
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