\(n_K=a\left(mol\right),n_{CaO}=b\left(mol\right)\)
\(m_X=39a+56b=37.75\left(g\right)\left(1\right)\)
\(\dfrac{39a}{56b}=\dfrac{39}{151}\left(2\right)\)
\(\left(1\right),\left(2\right):a=0.2,b=0.53\)
\(2K+2H_2O\rightarrow2KOH+H_2\)
\(0.2...................................0.1\)
\(V_{H_2}=0.1\cdot22.4=2.24\left(l\right)\)